Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A sled of mass 8 kg slides along the ice. It has an initial speed of 4 m/s but stops because of friction. How much work is done by friction?.

Sagot :

ayune

The work done by the friction force on the 8-kg sled is 64 Joule.

The work done by a force on an object is given by:

W = F . s

Where:

F = force

s = distance

Using the equation of motion:

v² = u² - 2 as

where:

v = final speed

u = initial velocity

a = acceleration

In this case v = 0 since the sled finally stops.

Hence,

0 = 4² - 2 as

2 as = 16

as = 8

Using the Newton's 2nd law of motion:

F = m . a

Where:

m = mass of the sled = 8

Substitute F = m . a into the work equation:

W = m . as

Substitute m = 8 and as = 8,

W = 8 x 8 = 64 Joule

Hence, the amount of work done is 64 Joule.

Learn more about work here:

https://brainly.com/question/25816840

#SPJ4

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.