Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A 3-kg mass attached to a string which goes vertically to a pulley rests on the floor. A weight is attached to the other end and released. If the 3-kg mass rises 50 cm in 1. 0 s, what is the mass of the weight?.

Sagot :

ayune

A weight is attached to the other end of the pulley and released, resulting in 3-kg mass to rise 50 cm in 1.0 s.  The mass of the weight is 3.68 kg

The problem can be solved using the equation of motion:

s = u . t + 1/2 a . t²

Where:

s = distance

u = initial velocity

t = time period

a = acceleration

Substitute the given parameters:

s = 50 cm = 0.5 m

u = 0

t = 1

Hence,

0.5 = 0 + 1/2 a . 1²

1/2 a = 0.5

a = 1 m/s²

After obtaining the acceleration, a, use the Newton's 2nd law of motion.

Forces acting on mass 3 kg : tension (T), weight (mg).

Hence,

T - mg = ma

T = m (g + a)

Let M = mass of the weight.

Forces acting on M : tension (T), weight (Mg). Hence,

Mg - T = Ma  

T = M (g - a)    (substitute T = m (g + a) )

m (g + a) = M (g - a)

M = m x (g + a) / (g - a)

  = 3 x  (9.8 + 1) / (9.8 - 1)

  = 3.68

Hence, the mass of the weight is 3.68 kg

Learn more about Newton's law here:

https://brainly.com/question/24994188

#SPJ4

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.