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A 3-kg mass attached to a string which goes vertically to a pulley rests on the floor. A weight is attached to the other end and released. If the 3-kg mass rises 50 cm in 1. 0 s, what is the mass of the weight?.

Sagot :

ayune

A weight is attached to the other end of the pulley and released, resulting in 3-kg mass to rise 50 cm in 1.0 s.  The mass of the weight is 3.68 kg

The problem can be solved using the equation of motion:

s = u . t + 1/2 a . t²

Where:

s = distance

u = initial velocity

t = time period

a = acceleration

Substitute the given parameters:

s = 50 cm = 0.5 m

u = 0

t = 1

Hence,

0.5 = 0 + 1/2 a . 1²

1/2 a = 0.5

a = 1 m/s²

After obtaining the acceleration, a, use the Newton's 2nd law of motion.

Forces acting on mass 3 kg : tension (T), weight (mg).

Hence,

T - mg = ma

T = m (g + a)

Let M = mass of the weight.

Forces acting on M : tension (T), weight (Mg). Hence,

Mg - T = Ma  

T = M (g - a)    (substitute T = m (g + a) )

m (g + a) = M (g - a)

M = m x (g + a) / (g - a)

  = 3 x  (9.8 + 1) / (9.8 - 1)

  = 3.68

Hence, the mass of the weight is 3.68 kg

Learn more about Newton's law here:

https://brainly.com/question/24994188

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