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what power must the pump supply to the system to pump the oil from the lower reservoir to the upper reservoir at a rate of 0.3 m3 /s? sketch the hgl and the egl for the system.

Sagot :

30.05 KW power must the pump supply to the system to pump oil from the lower reservoir to the upper reservoir at a rate of 0.3 m3/s.

P1/Pg + a1V12/2g + z1 + hp = P2/ Pg + a2 v22/2g + z2 + ∑h2

hp = 12 + [tex]v ^{2}[/tex]/2g [ 0.03 + fL/D +1 ]

Calculate the velocity

When an object is moving, its velocity serves as a measure of how quickly its location is changing as it is seen from a given point of view and as time is measured using a specific unit of measurement.

V= Q/A

  = Q/ [tex]\pi[/tex] [tex]D^{2}[/tex]/4

  = 0.2 / [tex]\pi[/tex] [tex][30]^{2}[/tex]

  = 2.83 ms/s

P = pgQ[tex]h_{p}[/tex]

P= ( 940kg/m3) (9.81 m/s2) (0.20 m3/s) (16.2m)

P= 300054.8 W (1Kw/ 1000W) = 30.05 kW

To learn more about reservoir

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