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Find the standard deviation for the binomial distribution which has the stated values of n and p.
n = 48
p = 3/5


Sagot :

The standard deviation for the binomial distribution is 3.39

The standard deviation for the binomial distribution is given by,

σ = [tex]\sqrt{n * P(1-P}[/tex]

where n = Number of trials

P = probability of success of an individual trail

If n = 48 and P = 0.6

σ = [tex]\sqrt{48 *0.6(1-0.6})[/tex]

= [tex]\sqrt{48*0.24}[/tex]

=[tex]\sqrt{11.52}[/tex]

=3.39

Therefore, the standard deviation for the binomial distribution will be 3.36.

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