Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The speed of the ball that hit straight up with an initial speed of 28 meters after 2.2 seconds it is hit = 6.44 m/s.
The speed of the ball
The magnitude of the velocity of an object in uniform motion is highly dependent on the magnitude of the initial velocity of the object and the acceleration experienced. Slowed down uniform motion is motion where the speed of an object always decreases every second, until the object stops.
By neglecting friction, the equation to determine the speed of the ball after t seconds:
v = v₀ - gt
We have,
Initial speed of the ball = 28 m/s ⇒ v₀
t = 2.2 s
The gravity acceleration = 9.81 m/s² ⇒ g
So, the speed of the ball:
v = 28 - (9.8) (2.2)
= 28 - 21.56
= 6.44 m/s
Learn more about speed of the object here: https://brainly.com/question/6504879
#SPJ4
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
