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Sagot :
The speed of the ball that hit straight up with an initial speed of 28 meters after 2.2 seconds it is hit = 6.44 m/s.
The speed of the ball
The magnitude of the velocity of an object in uniform motion is highly dependent on the magnitude of the initial velocity of the object and the acceleration experienced. Slowed down uniform motion is motion where the speed of an object always decreases every second, until the object stops.
By neglecting friction, the equation to determine the speed of the ball after t seconds:
v = v₀ - gt
We have,
Initial speed of the ball = 28 m/s ⇒ v₀
t = 2.2 s
The gravity acceleration = 9.81 m/s² ⇒ g
So, the speed of the ball:
v = 28 - (9.8) (2.2)
= 28 - 21.56
= 6.44 m/s
Learn more about speed of the object here: https://brainly.com/question/6504879
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