Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The work done w in terms of K₁ is (9/16)K₁..Work done is equal to change in kinetic energy of the body.
Since, it is given a electron is moving with Kinetic energy. We know that kinetic energy of any moving body is given by=(1/2)mv²
where m is defined as the mass of the body
and v is defined as the velocity of the body.
Initially K₁.=(1/2)[tex]m_e[/tex]v²
=>v²=2 K₁ / [tex]m_e[/tex]
=>v=√(2 K₁ / [tex]m_e[/tex])--------(eq1)
Now,velocity of body becomes one plus one-fourth of the above velocity,so new velocity is =[√(2 K₁ / [tex]m_e[/tex]) + [(1/4)×√(2 K₁ / [tex]m_e[/tex])]=(5/4)×√(2 K₁ / [tex]m_e[/tex].
Therefore, we know that work done is equal to change in kinetic energy of the body
=>W=(1/2)×[tex]m_e[/tex]×(v₂²-v₁²)
=>W=(1/2)×[tex]m_e[/tex] × ([(5/4)²×√(2 K₁ / [tex]m_e[/tex].)²- (√(2 K₁ / [tex]m_e[/tex]))²]
=>W=(1/2)×[tex]m_e[/tex] ×[(25/16)-1]×(2 K₁ / [tex]m_e[/tex].)
=>W=((25-16)/16)×K₁
=>W=(9/16)×K₁
Hence, work done in terms of K₁ is (9/16)K₁.
To know more about work, visit here:
https://brainly.com/question/18094932
#SPJ4
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
