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Sagot :
The equation of a line passes through (6,1) is 3x - 2y = 16.
Here we have to find the equation of a line.
Data given:
Point = (6,1)
The equation of another line is 2x + 3y = 18
From the given equation we can find the slope;
So we have
3y = -2x + 18
y = -2/3x + 18/3
So the slope is -2/3
As the line is perpendicular, so the slope of the line perpendicular to it will be 3/2
The general formula of the line is:
(y - y1) = m(x-x1)
(x1, y1) is the point
The point is (6,1 ) and the slope is 3/2
Now put that in the equation we get:
(y - 1) = 3/2(x - 6)
2y - 2 = 3x - 18
3x - 2y = 16
Therefore the equation is 3x - 2y = 16.
To know more about the equation of a line refer to the link given below:
https://brainly.com/question/18831322
#SPJ4
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