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The molar mass of hf is 20. 01 g/mol. How many moles of sn are required to react completely with 40 g of hf? 1 mole 2 moles 3 moles 4 moles.

Sagot :

Neetoo

The molar mass of HF is 20. 01 g/mol, (a) 1 mole of Sn is required to react completely with 40 g of HF.

Molar mass of HF = 20. 01 g/mol

Mass of HF = 40 g

Number of moles of Sn = ?

Write the balanced chemical equation

    Sn + 2HF   →   SnF₂ + H₂

one mole of Sn is required to react with two moles of HF

Find number of moles of HF

    number of moles = mass / molar mass

    number of moles of HF = 40 g / 20. 01

    number of moles of HF = 2.0 moles

As the molar ratio of Sn and HF 1 : 2

There are 2 moles of HF, and from the molar ratio, it is clear that the number of moles of Sn is half of HF.

    So the number of moles of Sn = 2 × 1/2

          number of moles of Sn = 1 mol

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