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Work and heat transfer are required per mass IS 40.6 kJ/k, 130 kJ/k for a r-134a at 320 kpa and 40 c undergoes an isothermal process in a closed system until its quality is 45 percent
A refrigerant experiences a problem with this query. a structured procedure in a closed system up until 45% quality in isothermal . We need to figure out how much heat transfer and effort are needed. Therefore, the equation Q equals two T provides the transfer for this keep. toward delta S. And the energy balance of a closed system is used to calculate the necessary work. E is that. The value of system will be e. Delta U will be equal to internal minus E out. Q less than w, out. He completed that portion, but we still need to calculate the entropy and internal energy one. They are all 1 34 a.when three 20 kilogramme paschals are given pleasure and the temperature is 40 °C. The entropy will thus be 1.452 kg jule paul, Casey kelvin according on table 8–13. and You will have an internal energy of 261.62 kg. What give you right now? We must ascertain the water and apple combination standards. Table 8 11. Temperature B should be set at 40°C and quality X should exactly equal 0.45. Entropy will then equal sf + X when taken as two from this point. the S F G. It will be equivalent to 0 39493 + 0.45 into 0.5 059 (zero point 39493). This will weigh 0.6-9-9 kilogrammes of juice. kz kelvin, please.The combined internal energy of the two of you will be Uf + X into U F G. which will be 107.39 plus 0.45 plus two = 107.39 + 0.45 + 2 = 43.61. It weighs 172 102 kg, Paul Casey. T into S one minus S two, which equals 313 into 1.452 minus 0.6 to 9 to zero, will now provide the heat transfer coefficient Q out. Thus, this will be 130 kZ. The amount of effort necessary will therefore equal U two less human plus Q out. It will be equivalent to 172.02 + 61.62 plus 13.1 in total. This comes out to 40.6.Recognize June But daisy and Q two out is equivalent to 1 30.2 kg Jewel park Az Joon Park Az, who weighs 40.6 kg, is the blue. So, here is the outcome.
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