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Sagot :
The probability of getting a red ball on the first draw and a white ball on the second is 0.3.
Total number of balls = 10
Now we have to pick: 4 red balls or 3 black balls or 3 white balls.
Case-1:
In this case we pick 4 red balls.
Now, probability for picking one red ball is 3/10. Now, the 2nd ball is drawn which is also red, probability for picking 2nd red ball is 2/19. probability for picking two red balls is
P(r) = (3/10) (2/9)
Case-2:
In this case we pick 3 white balls
Probability for picking 3 white balls
P(w) = (3/10) × (4/9)
Case-3:
probability for picking 03 black balls:
P(b) = (03/10) (02/9)
Therefore, probability for picking 2 same color balls:
= (3/10) (2/9) +(03/10) × (04/9) +(03/10) (02/9)
= 0.3
Learn more about Probability:
https://brainly.com/question/11234923
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