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Sagot :
Horizontal distance the base of the cliff does it strike the level ground below traveled is 138.564 m (r1/r2 = 1/3.)
Here Vertical component of Velocity = 800*sin(30) = 400 m/sec
s = ut + 0.5*g*t62
80 = 400t + 4.9t^2
t = 0.2 sec
Horizontal Component of velocity = 800*cos(30) = 692.82 m/sec
Therefore, Horizontal distance traveled = 692.82*0.2 = 138.564 m
When we give something a beginning velocity, we call that thing a projectile, and gravity has an impact on that thing. Horizontal range is the length of the horizontal axis for a projectile. It would also move before returning to the original vertical position. The horizontal range then depends on the launch angle (theta), initial velocity (V 0), and gravitational acceleration. When we throw or project an object, it becomes a projectile and is in motion. When a projectile moves, only one acceleration is present, and it is directed vertically. The acceleration brought on by gravity, in other words (g). Both the X-Axis and the Y-Axis can be used with the motion equations separately.
Learn more about Horizontal distance here:
https://brainly.com/question/11755354
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