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) a rifle bullet is fired at an angle of 30e below the horizontal with an initial velocity of 800 m/s from the top of a cliff 80 m high. how far from the base of the cliff does it strike the level ground below?

Sagot :

Horizontal distance the base of the cliff does it strike the level ground below traveled is  138.564 m (r1/r2 = 1/3.)

Here Vertical component of Velocity = 800*sin(30) = 400 m/sec

s = ut + 0.5*g*t62

80 = 400t + 4.9t^2

t = 0.2 sec

Horizontal Component of velocity = 800*cos(30) = 692.82 m/sec

Therefore, Horizontal distance traveled = 692.82*0.2 = 138.564 m

When we give something a beginning velocity, we call that thing a projectile, and gravity has an impact on that thing. Horizontal range is the length of the horizontal axis for a projectile. It would also move before returning to the original vertical position. The horizontal range then depends on the launch angle (theta), initial velocity (V 0), and gravitational acceleration. When we throw or project an object, it becomes a projectile and is in motion. When a projectile moves, only one acceleration is present, and it is directed vertically. The acceleration brought on by gravity, in other words (g). Both the X-Axis and the Y-Axis can be used with the motion equations separately.

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