Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The equation for circle is 28g + 16f =260
and the equation of tangent to this circle is y = [tex]\frac{6}{12}[/tex] x +29
a) the main equation of circle is ax + by +2gx+ 2fy +c =0 --------- (1)
Now,
putting the points (0,0) , (0,8) and (6,12) one by one, we get,
For the point (0,0), we get:
c =o ----------------------------- (2)
For the point (6,12), we get:
6x +12y + c = (6)² + (12)²
⇒ 6x +12y +c = 36 +144
⇒ 6x +12y +c = 180 --------------------------- (3)
For the point (0,8), we get,
8y + c = 64 ----------------------------- (4)
putting c=0,
8y +0 = 64
⇒ y =64/8
⇒ y = 8
Putting c=0 and y =8, we get,
6x + 12×8 +0 = 180
⇒ 6x + 96 =180
⇒ 6x = 84
⇒ x = 14
Putting all the values in equation (1), we get:
(14)² + (8)² +28g +16g + 0 = 0
⇒ 196 + 64 + 28g +16f =0
⇒ 28g + 16f = 260
b) As we know the tangent from the circle:
y = mx + c
⇒ 8 = -12/6 × 14 +c
⇒ c = 29
Therefore, the equation of the tangent is y = [tex]\frac{6}{12}[/tex]x + 29
Learn more about Tangent :
https://brainly.com/question/19424752
#SPJ4
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
