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A pentagon has 3 sides of length (2x-1) and 2 sides of length (x+5). If the perimeter is 127 what is the length of one of the longest sides.

Sagot :

The required length of one of the longest sides is 29 in the given pentagon.

The pentagon has 3 sides of length (2x - 1) and 2 sides of length (x + 5) and the perimeter of the pentagon is 127.

We know that the perimeter of the pentagon is the total length of all its sides, so we can set up the following equation:

3(2x - 1) + 2(x + 5) = 127

Apply the distributive property of multiplication,

6x - 3 + 2x + 10 = 127

Combine the likewise terms of the equation,

8x + 7 = 127

Finally, we can solve the equation by subtracting 7 from both sides and dividing both sides by 8:

8x = 120

x = 15

Therefore, the length of one of the longest sides is (2 × 15 - 1) = 29.

Learn more about the Perimeters here:

brainly.com/question/15287805

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