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Sagot :
Average area of the cross section plane of the solid which lies between the two parallel planes is equal to 197.4square feet.
As given in the question,
Number of parallel planes = 2
Distance between two parallel planes = 22 feet
Volume of the solid is equal to 4343 cubic feet
Let 'x' be the average area of cross section of the solid lies between two parallel planes.
Average area of cross section of the solid lies between two parallel planes = Volume of the solids / Distance between two parallel planes
⇒ x = 4343/22 square feet
⇒ x = 197.4 square feet
Therefore, the average area of the cross section of the solid lies between two parallel plane is equal to 197.4 square feet.
The complete question is:
A solid lies between two parallel planes 22 feet apart and has a volume of 4343 cubic feet. What is the average area of cross-sections of the solid by planes that lie between the given ones?
Learn more about average area here
brainly.com/question/17595469
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