Answered

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two children sit on a seesaw such that a 300-n child is 2.00 m from the fulcrum. where should a second child of weight 375 n sit in order to balance the system if the support is at the center of the plank?

Sagot :

The second child should be at 1.6 m in order to balance the seesaw.

The equation of torque is given as,

τ = r * F sinθ

where, r is the distance from the fulcrum

F is the force

From the above equation, as the seesaw is in equilibrium, this means that left side is equal to right side, we can write

τ₁ = τ₂

r₁ * F₁ = r₂ * F₂

In order to calculate the amount of torque the right side is providing to the system, we need to find out the distance r₂ that the person on the right is sitting with respect to the fulcrum.

300 * 2 = 375 * r₂

r₂ = 600/375 = 1.6 m

Thus, the second child should sit at 1.6 m in order to balance the seesaw.

To know more about torque:

https://brainly.com/question/11735028

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