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Sagot :
The mole fraction of the NH₃ in the solution is 0.0955.
given that :
mass of the NH₃ = 25 g
mass of the H₂O = 250 g
moles of the NH₃ = 25 g/ 17.03 g /mol
= 1.468 mol
moles of the H₂O = 250 g/ 18 g /mol
= 13.88 mol
total moles = 15.36 mol
the mole fraction of NH₃ = moles of NH₃ / total moles
= 1.468 / 15.36
= 0.0955
Thus, A solution is prepared by bubbling NH₃ in water until 25 g of nh3 dissolves. the final solution weighs 250 g and the density of the solution is 0.974 g/ml. the mole fraction of NH₃ in the solution is 0.0955.
To learn more about mole fraction here
https://brainly.com/question/15883465
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