TiffaniBeu
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

In one generation, the frequency of the A allele is 70 percent and the frequency of the a allele is 30 percent. What are the chances of an individual in the next generation having the genotype aa if the population is in genetic equilibrium? 49% 42% 30% 9%

Sagot :

9%

Why?
The frequency for allele a is 30% or 0.3. Let's call this frequency p.
p^2 would then represent the frequency of genotype aa (this is is derived from the formula p^2+2pq+q^2=1 where p and q represent alleles a and A respectively. So p^2=aa, pq=Aa and q^2=AA)
0.3^2=0.09 or 9%

Answer:

The correct answer would be 9%.

As the population is in genetic equilibrium, then the population must be following the Hardy-Weinberg equations:

p + q  = 1 and

p² + q² + 2pq = 1

The frequency of A (dominant allele) in a population is 70 percent.

Thus, the value of p would be 70/100 which comes out be 0.7

Similarly, the value of q would be equal to 0.3

The frequency of individual with homozygous recessive genotype, that is, aa would be equal to q².

So, q² = [tex](0.3)^{2}[/tex] ⇒ 0.09

Thus, the frequency of individual with genotype aa would be equal to 9 percent.

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.