TiffaniBeu
Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

In one generation, the frequency of the A allele is 70 percent and the frequency of the a allele is 30 percent. What are the chances of an individual in the next generation having the genotype aa if the population is in genetic equilibrium? 49% 42% 30% 9%

Sagot :

9%

Why?
The frequency for allele a is 30% or 0.3. Let's call this frequency p.
p^2 would then represent the frequency of genotype aa (this is is derived from the formula p^2+2pq+q^2=1 where p and q represent alleles a and A respectively. So p^2=aa, pq=Aa and q^2=AA)
0.3^2=0.09 or 9%

Answer:

The correct answer would be 9%.

As the population is in genetic equilibrium, then the population must be following the Hardy-Weinberg equations:

p + q  = 1 and

p² + q² + 2pq = 1

The frequency of A (dominant allele) in a population is 70 percent.

Thus, the value of p would be 70/100 which comes out be 0.7

Similarly, the value of q would be equal to 0.3

The frequency of individual with homozygous recessive genotype, that is, aa would be equal to q².

So, q² = [tex](0.3)^{2}[/tex] ⇒ 0.09

Thus, the frequency of individual with genotype aa would be equal to 9 percent.

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.