DustinM
Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Please Help!?!

4. A data set has a variance of 42.

What is the standard deviation of the data set?

Round to the nearest tenth.



Question 5.5. What is the standard deviation of the data set? Round your answer to the nearest tenth.

6 4 9 5 5 4 5

(Points : 1)
1.6
1.7
5.4
5.0

Sagot :

Q4 . Standard deviation is square root of variance so, the standard deviation of the given data set is , [tex]\sqrt { 42 } [/tex] which is equal to 6.48074069841

Q5.5 

To find the standard variation first find the mean of the set.

6+4+9+5+5+4+5 = 38 

[tex]\frac { 38 }{ 7 } =5.42[/tex]

Then we will subtract the mean from each number in the set, then will square that. Then we will add those all. 

Solution is in the pic. Sorry if this was not explanatory enough.

Ask me if you wanna know more.
View image Аноним
boffeemadrid

Answer:

Step-by-step explanation:

(A) It is given that a data set has a variance of 42, then the standard deviation is given as:

[tex]SD=\sqrt{variance}[/tex]

⇒[tex]SD=\sqrt{42}[/tex]

⇒[tex]SD=6.48[/tex]

Thus, the standard deviation of the given data set is 6.48.

(B) The given data set is:

6 4 9 5 5 4 5

Mean of the given data set is:

[tex]Mean=\frac{6+4+9+5+5+4+5}{7}[/tex]

[tex]Mean=\frac{38}{7}[/tex]

[tex]Mean=5.42[/tex]

Data set                                                            [tex](x-\overline{x})^2[/tex]

6                                                                                0.33

4                                                                                2.01

9                                                                               12.81

5                                                                               0.17      

5                                                                               0.17    

4                                                                                2.01

5                                                                               0.17    

The variance is given as:

[tex]V=\frac{0.33+2.01+12.81+0.17+0.17+2.01+0.17}{7}[/tex]

[tex]V=2.52[/tex]

Thus, the standard deviation is given as:

[tex]SD=\sqrt{variance}[/tex]

⇒[tex]SD=\sqrt{2.52}[/tex]

⇒[tex]SD=1.6[/tex]          

Hence, option A is correct.                  

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.