Answered

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(2x^2-17x-38)/(2x+3)

Sagot :

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(2x^2-17x-38)/(2x+3)
=-15x^2-38)/2x+3)
=-7.5x^2/2x+3
=-3.525x-38+3
=-3.525x-35
(2x^2-17x-38)=(2x+3)(x-10)+8
(2x^2-17x-38)/(2x+3)=x-10+8
(2x^2-17x-38)/(2x+3)=x-2
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