At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer: 1040 feet.
Step-by-step explanation:
We know that , Perimeter of a rectangle = 2 (length +width)
As per given , we have
Length of football ground = [tex]53\dfrac{1}{3}\text{yards}=\dfrac{53\times3+1}{3}\text{yards}=\dfrac{160}{3}\text{ yards}[/tex]
Width = 120 yards
Since, the football ground is rectangle in shape.
Then , Perimeter of the ground = [tex]2(\dfrac{160}{3}+120)[/tex] yards
[tex]=2(\dfrac{160+3(120)}{3})[/tex] yards
=[tex]2(\dfrac{160+360}{3})[/tex]yards
[tex]=2(\dfrac{520}{3})[/tex] yards
[tex]=\dfrac{1040}{3}[/tex] yards
Also, 1 yard =3 feet
i.e. Perimeter = [tex]\dfrac{1040}{3}\times3=1040[/tex] feet
Hence, the required perimeter is
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.