Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predict the population after 10 years

Sagot :

taskmasters
1.       So the current population of the town is 15 200 and is growing per year with 2%.
Find the population number after 10 years.
First, let’s find the value of 2%  in decimal form
=> 2/100
=> 0.02

Now, let’s try to solve
Population = 15 200 ( 1 + (0.02 x 10) )
Population = 15 200 ( 1 + 0.2 )
Population = 15 200 + 3040
Population =  18 240
Thus, in 10 years, the town’s population will increase to 18 240.



Answer:

The equation model is P = Po * e^rt

The population after 10 years = 18, 559 (most approximately)

Step-by-step explanation:

We use formula to find the population growth.

P = Po * e^rt

Where P is the total population after t years

Po is the initial population

r = rate of growth

t = time

e = 2.71 [Euler number]

The equation model is P = Po * e^rt

Now to find the population after 10 years, we have to plug in the given values in the formula.

Given:

Po = 15, 200, r = 2% = 2/100 = 0.02, and t = 10 years

P = 15,200*e^0.02(10)

P = 15,200*2.71^0.2

P = 15,200 *1.221

P = 18, 559

Therefore, the population after 10 years = 18, 559 (most approximately)

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.