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Sagot :
1.
So the current population of the town is 15 200
and is growing per year with 2%.
Find the population number after 10 years.
First, let’s find the value of 2% in decimal form
=> 2/100
=> 0.02
Now, let’s try to solve
Population = 15 200 ( 1 + (0.02 x 10) )
Population = 15 200 ( 1 + 0.2 )
Population = 15 200 + 3040
Population = 18 240
Thus, in 10 years, the town’s population will increase to 18 240.
Find the population number after 10 years.
First, let’s find the value of 2% in decimal form
=> 2/100
=> 0.02
Now, let’s try to solve
Population = 15 200 ( 1 + (0.02 x 10) )
Population = 15 200 ( 1 + 0.2 )
Population = 15 200 + 3040
Population = 18 240
Thus, in 10 years, the town’s population will increase to 18 240.
Answer:
The equation model is P = Po * e^rt
The population after 10 years = 18, 559 (most approximately)
Step-by-step explanation:
We use formula to find the population growth.
P = Po * e^rt
Where P is the total population after t years
Po is the initial population
r = rate of growth
t = time
e = 2.71 [Euler number]
The equation model is P = Po * e^rt
Now to find the population after 10 years, we have to plug in the given values in the formula.
Given:
Po = 15, 200, r = 2% = 2/100 = 0.02, and t = 10 years
P = 15,200*e^0.02(10)
P = 15,200*2.71^0.2
P = 15,200 *1.221
P = 18, 559
Therefore, the population after 10 years = 18, 559 (most approximately)
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