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Solve the system of equations using substitution.

y = 3x + 1
y = 4x

a (1, 4)
b (0.1, 0.6)
c (-1, -4)
d (-4, -1)

Sagot :

[tex]y=3x+1\\ y=4x\\\\ 3x+1=4x\\ 4x-3x=1\\ x=1\\\\ y=4\cdot1\\ y=4\\\\ \boxed{(x,y)=(1,4)}[/tex]
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