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A new cruise ship line has just launched 3 new ships: the Pacific Paradise, the Carribean Paradise, and the Mediterranean Paradise. The Carribean Paradise has 18 more deluxe staterooms than the Pacific Paradise. The Mediterranean Paradise has 25 fewer deluxe staterooms than three times the number of deluxe staterooms on the Pacific Paradise. Find the number of staterooms for each of the ships if the total number of deluxe staterooms for all three ships is 928

Sagot :

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Let x = Pacific Paradise
You can set up the equation like this:
x + (3x - 25) + (x + 18) = 928
(Combine like-terms)
5x - 7 = 928
(Add 7 to both sides)
5x = 935
(divide by 5 to both sides)
x = 187 (# of deluxe staterooms Pacific Paradise)

Next to find the # of deluxe staterooms of the other cruise ships create two equations

Let y = Carribean Paradise
x + 18 = y
(plug in the value of x which is 187)
187 + 18 = y
(combine like-terms)
205 = y (# of deluxe staterooms Carribean Paradise)

Let z = Mediterranean Paradise
3x - 25 = z
(plug in the value of x which is 187)
3(187) - 25 = z
(follow PEMDAS to simplify and combine like-terms)
536 = z (# of deluxe staterooms Mediterranean Paradise)

Finally check your answer by adding up all of your answers to make sure it equals 928

536 + 205 + 187 = ? (928!)



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