At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Jordans have a rectangular garden. want to build a diagonal pathway across he garden. the length of pathway is 90 ft. width of garden is 5 times more than 2 times the length of garden. what is length of garden?

Sagot :

P=2l+2w
w=5(2l)
45=10l
4.5=l
---------------
P=2l+2(5(2l))
P=2l+20l
P=22l
P=99
so we see the pythagorean theorem
a^2+b^2=c^2
diagonal=c
width=a or b, pick one
width=a
legnth=b
width is 5 times more than 2 times legnth of garden
w=5(2legnth)
this doesn't make sense since the legnth is normally longer than the width, but we'll stick with that
w=5(2l)
w=10l
a=10b
(10b)^2+b^2=90^2
100b^2+b^2=8100
101b^2=8100
divide by 101
b^2=80.198 aprox 80.2
square root
8.95533
legnth of garden =8.96
to find width subsitue
w=10l
w=89.56

legnth=8.96
width=89.56
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.