At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
x - Orville's age
y - Wilbur's age
Five years ago, Orville was twice as old as Wilbur.
[tex]x-5=2(y-5) \\ x-5=2y-10 \\ x=2y-10+5 \\ x=2y-5[/tex]
Five years from now, Orville will be one and one half times as old as Wilbur.
[tex]x+5=1 \frac{1}{2}(y+5) \\ x+5=\frac{3}{2}(y+5) \\ x+5=\frac{3}{2}y+\frac{15}{2} \\ x=\frac{3}{2}y+\frac{15}{2}-5[/tex]
Set both expressions equal to each other:
[tex]x=x \\ 2y-5=\frac{3}{2}y+\frac{15}{2}-5 \ \ \ |+5 \\ 2y=\frac{3}{2}y+\frac{15}{2} \ \ \ |\times 2 \\ 4y=3y+15 \\ 4y-3y=15 \\ y=15 \\ \\ x=2y-5=2 \times 15-5=30-5=25 [/tex]
Orville is 25 years old.
Wilbur is 15 years old.
y - Wilbur's age
Five years ago, Orville was twice as old as Wilbur.
[tex]x-5=2(y-5) \\ x-5=2y-10 \\ x=2y-10+5 \\ x=2y-5[/tex]
Five years from now, Orville will be one and one half times as old as Wilbur.
[tex]x+5=1 \frac{1}{2}(y+5) \\ x+5=\frac{3}{2}(y+5) \\ x+5=\frac{3}{2}y+\frac{15}{2} \\ x=\frac{3}{2}y+\frac{15}{2}-5[/tex]
Set both expressions equal to each other:
[tex]x=x \\ 2y-5=\frac{3}{2}y+\frac{15}{2}-5 \ \ \ |+5 \\ 2y=\frac{3}{2}y+\frac{15}{2} \ \ \ |\times 2 \\ 4y=3y+15 \\ 4y-3y=15 \\ y=15 \\ \\ x=2y-5=2 \times 15-5=30-5=25 [/tex]
Orville is 25 years old.
Wilbur is 15 years old.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.