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Sagot :
Call the numbers x and y. Let y be the larger number.
The second of 2 numbers is 5 more than twice the first is y = 2x+5
Their sum is 29 is x+y=29.
Substitute 2x+5 for y in the second equation.x+2x+5=29
3x=24
x=8
y = 2(8) + 5 = 21
Hope the solution helped.
Briemode!:)
The second of 2 numbers is 5 more than twice the first is y = 2x+5
Their sum is 29 is x+y=29.
Substitute 2x+5 for y in the second equation.x+2x+5=29
3x=24
x=8
y = 2(8) + 5 = 21
Hope the solution helped.
Briemode!:)
so call the numbers x and z
first number=x
second number=z
second of 2 numbers (z) is = 5 more than (5+) twice the first (2x)
z=5+2x
their sum is 29
x+z=29
subsisute 5+2x for z in equation
x+5+2x=29
3x+5=29
subtract 5
3x=24
divide bboth sides by 3
x=8
subsitute 8 for x
z=5+2(8)
z=5+16
z=21
numbers are 8 and 21
first number=x
second number=z
second of 2 numbers (z) is = 5 more than (5+) twice the first (2x)
z=5+2x
their sum is 29
x+z=29
subsisute 5+2x for z in equation
x+5+2x=29
3x+5=29
subtract 5
3x=24
divide bboth sides by 3
x=8
subsitute 8 for x
z=5+2(8)
z=5+16
z=21
numbers are 8 and 21
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