Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Call the numbers x and y. Let y be the larger number.
The second of 2 numbers is 5 more than twice the first is y = 2x+5
Their sum is 29 is x+y=29.
Substitute 2x+5 for y in the second equation.x+2x+5=29
3x=24
x=8
y = 2(8) + 5 = 21
Hope the solution helped.
Briemode!:)
The second of 2 numbers is 5 more than twice the first is y = 2x+5
Their sum is 29 is x+y=29.
Substitute 2x+5 for y in the second equation.x+2x+5=29
3x=24
x=8
y = 2(8) + 5 = 21
Hope the solution helped.
Briemode!:)
so call the numbers x and z
first number=x
second number=z
second of 2 numbers (z) is = 5 more than (5+) twice the first (2x)
z=5+2x
their sum is 29
x+z=29
subsisute 5+2x for z in equation
x+5+2x=29
3x+5=29
subtract 5
3x=24
divide bboth sides by 3
x=8
subsitute 8 for x
z=5+2(8)
z=5+16
z=21
numbers are 8 and 21
first number=x
second number=z
second of 2 numbers (z) is = 5 more than (5+) twice the first (2x)
z=5+2x
their sum is 29
x+z=29
subsisute 5+2x for z in equation
x+5+2x=29
3x+5=29
subtract 5
3x=24
divide bboth sides by 3
x=8
subsitute 8 for x
z=5+2(8)
z=5+16
z=21
numbers are 8 and 21
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.