At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Josiah and his friends are going to the movies. Each ticket costs $10, and popcorn is $5 a bag. There is a $3 service fee for the entire purchase. He has $75. If he buys 4 tickets, how many bags of popcorn can he buy? if x=number of tickets and y=number of popcorn which of the following inequalities would you use to answer the problem?

A x+y=75
B 10x+5y+3≤75
C 10x+5y≤75
D 10x+5y+3≥75


Sagot :

B
Because if x equals the number of tickets the it would be 10 X x. Same with the popcorn. for example: x=5 And y =3. it would be
10(5)+5(3)+3=$68

Answer:

B.

Step-by-step explanation:

If each ticket costs $10 and each popcorn costs $5, with x = number of tickets and y = number of popcorn and $3 the service we have

10x+5y+3 = total cost.

Now, he has a total of $75 and he buys 4 tickets so

10(4)+5y+3 = 75

40+5y+3 = 75

43+5y=75

5y = 75-43

5y = 32

y = 32/5 = 6.4 ≈ 6 popcorn.

Then, he can buy 6 popcorns. Now, to find the inequality we need to know that if he has $75, the total cost can't exceed $75, that is, the total cost needs to be less or equal to $75.

10x+5y+3 ≤75.