Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Describe the vertical asymptote(s) and hole(s) for the graph of y = (x-5)(x-2) over (x-2)(x+4).

Sagot :

dln
To find where there are holes, we need to make the function = [tex] \frac{0}{0} [/tex].
[tex] \frac{(x-5)(x-2)}{(x-2)(x+4)} [/tex]
If you plug in [tex]x=2[/tex], you get [tex] \frac{0}{0} [/tex], which means there is a hole in the graph when [tex]x=2[/tex]

To find where there are vertical asymptotes, we need to make just the bottom 0.
Ex. [tex] \frac{1}{0} [/tex]
[tex] \frac{(x-5)(x-2)}{(x-2)(x+4)} [/tex]
If you plug in [tex]x=-4[/tex], you get [tex] \frac{(-9)(-6)}{0} = \frac{54}{0} [/tex], which means there is a vertical asymptote when [tex]x=-4[/tex]
awhitsett08

Answer:

X=-3 ,-1

Step-by-step explanation:

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.