Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

what are the first four terms of the sequence represented by the expression n(n-2)-3

Sagot :

naǫ
[tex]a_n=n(n-2)-3 \\ \\ a_1=1(1-2)-3=1 \times (-1)-3=-1-3=-4 \\ a_2=2(2-2)-3=2 \times 0-3=0-3=-3 \\ a_3=3(3-2)-3= 3 \times 1-3=3-3=0 \\ a_4=4(4-2)-3=4 \times 2 -3 =8-3 =5 [/tex]

The first four terms are -4, -3, 0, 5.

Answer:

As per the statement:

Given a sequence:

[tex]a_n = n(n-2)-3[/tex]

where, n is the number of terms;

We have to find the first four terms of this sequence:

For n =1

[tex]a_1 = 1(1-2)-3 =1(-1)-3 = -1-3 = -4[/tex]

⇒[tex]a_1 = -4[/tex]

For n =2

[tex]a_2= 2(2-2)-3 =2(0)-3 = 0-3 = -3[/tex]

⇒[tex]a_2 = -3[/tex]

For n =3

[tex]a_3 = 3(3-2)-3 =3(1)-3 = 3-3 = 0[/tex]

⇒[tex]a_3= 0[/tex]

For n =4

[tex]a_4 = 4(4-2)-3 =4(2)-3 = 8-3 = 5[/tex]

⇒[tex]a_4= 5[/tex]

Therefore, the first four terms of the sequence are:

-4, -3, 0 , 5

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.