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Sagot :
jill=j
meg=m
beth=b
jill is 2 years younger than meg
therefor if we add 2 to jill age we get meg's age
j+2=m
beth is 1/2 as old as meg
therefor 1/2 of megs age=beth's age
b=1/2m
j+2=m
b=1/2m
meg=m
beth=b
jill is 2 years younger than meg
therefor if we add 2 to jill age we get meg's age
j+2=m
beth is 1/2 as old as meg
therefor 1/2 of megs age=beth's age
b=1/2m
j+2=m
b=1/2m
Answer:
The algebraic expressions are
x = m + 2
[tex]y = \frac{m}{2}[/tex]
Step-by-step explanation:
As given
Jill , meg and Beth are sisters.
Let m is represented the age of the meg.
Let x is represented the age of the jill.
Let y is represented the age of the Beth.
As given
Jill is 2 yrs younger than meg .
Thus
x = m + 2
As given
Beth is half as old as meg.
Thus
[tex]y = \frac{m}{2}[/tex]
Therefore the algebraic expression are
x = m + 2
[tex]y = \frac{m}{2}[/tex]
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