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Sagot :
First we need to find out the time it took for the truck to reach town B.
[tex]Speed= \frac{Distance}{Time}[/tex]
[tex]40= \frac{200}{T} [/tex]
[tex]T=5hours[/tex]
Now, because the van left 1.5 hours earlier and reached the destination 2.5 hours before, it took 1 hour less the the truck to arrive.
[tex]5hours-1hour=4hours[/tex] which is the time it took for the van to arrive.
Now we use the speed equation again to work out speed.
[tex]Speed= \frac{200}{4} [/tex]
[tex]Speed=50mph[/tex] = speed of van
Hope this helped :)
[tex]Speed= \frac{Distance}{Time}[/tex]
[tex]40= \frac{200}{T} [/tex]
[tex]T=5hours[/tex]
Now, because the van left 1.5 hours earlier and reached the destination 2.5 hours before, it took 1 hour less the the truck to arrive.
[tex]5hours-1hour=4hours[/tex] which is the time it took for the van to arrive.
Now we use the speed equation again to work out speed.
[tex]Speed= \frac{200}{4} [/tex]
[tex]Speed=50mph[/tex] = speed of van
Hope this helped :)
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