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How far does the tip of a 14cm long minute hand on a clock move in 10 minutes?

Sagot :

jjonathon7
circumference = pi x diamater
radius = 14cm
diamater= 2r = 28cm
60 minutes in hour for one full rotation
10 minutes = 1/6 and hour
it travels (28 x pi) / 6
okpalawalter8

We have that The the tip of a 14cm long minute hand on a clock moves [tex]x=14.6608 cm[/tex] in 10 minutes,Giving the correct Answer to be [tex]x=14.6608 cm[/tex]

From the question we are told that:

Length of Minute Hand [tex]l=14cm[/tex]

Time [tex]T=10 minutes[/tex]

Generally the angle covered in time T is mathematically given as

Since

[tex]60 minutes =360 \textdegree[/tex]

Therefore

 [tex]\theta=\frac{T}{60}*360[/tex]

 [tex]\theta=\frac{10}{60}*360[/tex]

 [tex]\theta=60 \textdegree[/tex]

 [tex]\theta= 1.0472 rad[/tex]

Therefore

The distance covered by the tip of the minute hand is

 [tex]x=\theta*r[/tex]

Where

Length of Minute Hand l=Radius r

 [tex]x=1.0472*14\\\\[/tex]

 [tex]x=14.6608 cm[/tex]

In conclusion

The the tip of a 14cm long minute hand on a clock moves [tex]x=14.6608 cm[/tex] in 10 minutes

For more information on this visit

https://brainly.com/question/23729577

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