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what is the solution to 3 times the square root of 4 minus 2 times the square root of 4

Sagot :

naǫ
[tex]3\sqrt{4}-2\sqrt{4}=(3-2)\sqrt{4}=\sqrt{4}=\sqrt{2^2}=2[/tex]
3 √4 - 2√4
(3 - 2) √4
√4
2
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