MarthaMwamba5
Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

the sum of three numbers is 61. the second number is 6 times the first. and the third number is 5 more than the second. find the numbers

Sagot :

[tex]x-the\ first\ number\\6x-the\ second\ number\\6x+5-the\ third\ number\\\\(x)+(6x)+(6x+5)=61\\x+6x+6x+5=61\\13x+5=61\ \ \ \ |subtract\ 5\ from\ both\ sides\\13x=56\ \ \ \ |divide\ both\ sides\ by\ 13\\\boxed{x=\frac{56}{13}\to x=4\frac{4}{13}-the\ first\ number}\\\boxed{6x=6\cdot\frac{56}{13}=\frac{336}{13}=25\frac{11}{13}-the\ second\ number}\\\boxed{6x+5=25\frac{11}{13}+5=30\frac{11}{13}-the\ third\ number}[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.