ProPeace
Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

[tex]9X^2-12X+4=0[/tex] X=?

Sagot :

konrad509
[tex]9x^2-12x+4=0\\ (3x-2)^2=0\\ 3x-2=0\\ 3x=2\\ x=\dfrac{2}{3} [/tex]
ValyRemus
[tex]9x^2-12x+4=0[/tex] 

[tex](3x)^2-2\cdot 2\cdot3x+2^2=0[/tex]

[tex](3x-2)^2=0, but...(3x-2)^2 \geq 0[/tex] , ∨ x∈R

[tex]So, (3x-2)^2=0[/tex]

[tex]3x-2=0[/tex] ⇒ [tex]3x=2[/tex] ⇒ [tex]\boxed { x= \frac{2}{3} }[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.