Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

x + 8y = 27; (–5, 5)

a. y = 1/8x + 45
b. y = 8x + 45
c. y = -8x + 45
d. y = 1/8x - 45



Sagot :

iGreen
First, let's re-arrange to slope-intercept form.

x + 8y = 27

Subtract 'x' to both sides:

8y = -x + 27

Divide 8 to both sides:

y = -1/8x + 3.375

So the slope of this line is -1/8, to find the slope that is perpendicular to this, we multiply it by -1 and flip it. -1/8 * -1 = 1/8, flipping it will give us 8/1 or 8.

So the slope of the perpendicular line will be 8.

Now we can plug this into point-slope form along with the point given.

y - y1 = m(x - x1)

y - 5 = 8(x + 5)

y - 5 = 8x + 40

y = 8x + 45
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.