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4y+5x=15
x=8y+3

I am in Algebra 1 and kind of stuck on this problem. Can anyone help me out

Sagot :

4y+5x=15x=8y+3

4y+5*(8y+3)=15

4y+40y+15=15

44y=0

y=0

x=8y+3

x=8*0+3

x=3
ValyRemus
[tex]If...x=8y+3[/tex] ⇒ [tex]4y+5x=4y+5\cdot(8y+3)=4y+40y+15=44y+15[/tex]

[tex]44y+15=15[/tex] ⇒ [tex]44y=0[/tex] ⇒ [tex]\boxed {y=0}[/tex]

[tex]x=8\cdot0+3[/tex] [tex]\boxed { x=3 }[/tex]
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