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how do you solve the equation 0.4(2x+0.5)=3[0.2x+(-2)]-4

Sagot :

 0.4(2x+0.5)=3[0.2x+(-2)]-4 

 0.8x+0.2=0.6x-6-4  

0.8x-0.6x=-6-4-0.2 

 0.2x=-10.2  

x=-10.2/0.2 

 x=-51
[tex]0.4(2x+0.5)=3[0.2x+(-2)]-4[/tex]

[tex]0.8x+0.2=0.6x-10[/tex]

[tex]0.2x=-10.2[/tex]

[tex]x= \frac{-10.2}{0.2} [/tex]

[tex]x=-51[/tex]