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Sagot :
a) [tex]y=mx+c[/tex]
[tex]m=gradient=-725[/tex]
[tex]y(v)-intercept=8000[/tex]
b) [tex]5100=8000-725t[/tex]
[tex]2900=725t[/tex]
[tex]t=4[/tex]
The value will be 5100 after 4 years.
c) [tex]V=8000-725(9)[/tex]
[tex]V=8000-6525[/tex]
[tex]V=1475[/tex]
The value of the jet will be 1475 after 9 years.
Hope I helped bro, now i can sleep
[tex]m=gradient=-725[/tex]
[tex]y(v)-intercept=8000[/tex]
b) [tex]5100=8000-725t[/tex]
[tex]2900=725t[/tex]
[tex]t=4[/tex]
The value will be 5100 after 4 years.
c) [tex]V=8000-725(9)[/tex]
[tex]V=8000-6525[/tex]
[tex]V=1475[/tex]
The value of the jet will be 1475 after 9 years.
Hope I helped bro, now i can sleep
So:
[tex]V=8000-725t\quad \{ 0\le t\le 11\} [/tex]
*V (in dollars) stands for the depreciated or non depreciated value of the jet ski.
*t (in years) stands for the amount of time that has passed. t is greater or equal to 0 and less than or equal to 11.
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Question (a):
Now V is a function of t. V=f(t).
When t=0, V=0 --> Point:(0,0)
When t=2, V=6550 --> Point (2, 6550)
When t=4, V=5100 --> Point (4, 5100)
When t=6, V=3650 --> Point (6, 3650)
When t=8, V=2200 --> Point (8,2200)
When t=11, V=25 --> Point: (11, 25)
So as the graph V=8000-725t is LINEAR, we can draw a line through the points mentioned above.
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Question (b): After how many years will the jet ski be worth $5100?
[tex]8000-725t=5100\\ \\ 8000-5100=725t\\ \\ 2900=725t\\ \\ \frac { 2900 }{ 725 } =t\\ \\ \therefore \quad t=4,\quad when\quad V=5100[/tex]
Answer: 4 years.
-----------------------
Question (c): What will be the value of the jet ski after 9 years?
[tex]When\quad t=9,\\ \\ V=8000-725\left( 9 \right) \\ \\ =1475[/tex]
The answer is $1,475.00
[tex]V=8000-725t\quad \{ 0\le t\le 11\} [/tex]
*V (in dollars) stands for the depreciated or non depreciated value of the jet ski.
*t (in years) stands for the amount of time that has passed. t is greater or equal to 0 and less than or equal to 11.
-------------------
Question (a):
Now V is a function of t. V=f(t).
When t=0, V=0 --> Point:(0,0)
When t=2, V=6550 --> Point (2, 6550)
When t=4, V=5100 --> Point (4, 5100)
When t=6, V=3650 --> Point (6, 3650)
When t=8, V=2200 --> Point (8,2200)
When t=11, V=25 --> Point: (11, 25)
So as the graph V=8000-725t is LINEAR, we can draw a line through the points mentioned above.
------------------------
Question (b): After how many years will the jet ski be worth $5100?
[tex]8000-725t=5100\\ \\ 8000-5100=725t\\ \\ 2900=725t\\ \\ \frac { 2900 }{ 725 } =t\\ \\ \therefore \quad t=4,\quad when\quad V=5100[/tex]
Answer: 4 years.
-----------------------
Question (c): What will be the value of the jet ski after 9 years?
[tex]When\quad t=9,\\ \\ V=8000-725\left( 9 \right) \\ \\ =1475[/tex]
The answer is $1,475.00
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