Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
In humans, tongue rolling is dominant to the inability to tongue roll. The chances a child will be a non-tongue roller is C. 0.5.
Answer:
The chances of a child being non - tongue roller is [tex]0.5\\[/tex]
Explanation:
Let the allele for dominant "tongue rolling trait" be represented by "T"
The allele for recessive "non-tongue rolling trait" be represented by "t"
The genotype of a heterozygous tongue rolling parent will be "Tt"
The genotype of a homozygous non- tongue rolling parent will be "tt"
If a cross is carried out between these two individuals , the offspring produced are as shown in the punnet square below-
T t
t Tt tt
t Tt tt
So the number of offsrpings which are non- tongue roller are two in numbers represented by "tt"
So the chances that a child will be a non-tongue roller are
[tex]\frac{2}{4} \\= 0.5\\[/tex]
Where , "4" represents the total number of offsprings produced
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.