Regena746
Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

In humans tongue rolling is dominant to the inability to tongue roll. If a heterozygous tongue roller and a non-tongue roller have a child, what are the chances the child will be a non-tongue roller? A. 0 B. 0.25 C. 0.5 D. 0.75

Sagot :

lrathburn
In humans, tongue rolling is dominant to the inability to tongue roll. The chances a child will be a non-tongue roller is C. 0.5.

Answer:

The chances of a child being non - tongue roller is [tex]0.5\\[/tex]

Explanation:

Let the allele for dominant "tongue rolling trait" be represented by "T"

The allele for recessive  "non-tongue rolling trait" be represented by "t"

The genotype of a heterozygous tongue rolling parent will be "Tt"

The genotype of a homozygous non- tongue rolling parent will be "tt"

If a cross is carried out between these two individuals , the offspring  produced are as shown in the punnet square below-

T t

t Tt tt

t Tt tt

So the number of offsrpings which are non- tongue roller are two in numbers represented by "tt"

So the chances that a child will be a non-tongue roller are

[tex]\frac{2}{4} \\= 0.5\\[/tex]

Where , "4" represents the total number of offsprings produced

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.