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a ship is 45 miles east and 30 miles south of port. if the captain wants to sail directly to south port, what beating sold be taken

Sagot :

apologiabiology
probaly you meant  'what bearing should be taken'

so use pythagorean theorem
c=distance from position to south port
b=45
a=30

a^2=B^2=c^2
30^2+45^2=c^2
900+2025=c^2
2925=c^2
square root of both sides
15 times √13
aprox
54.08
54.1
opposite of east=west
opposite of south=north

bearing=
54.1 miles north-west
Well
          East
45 miles > > > >
   <                   v
         <             v 30 miles South
 North      <      v
       West       <  Δ= ship

A right angle is formed, so we use Pythagoras.

[tex]45 ^{2} +30 ^{2}=2925 [/tex]
[tex] \sqrt{2925}=54.08 [/tex]

Therefore,  the route should be 54 miles North West
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