Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
By "standard" I assume you mean "slope-intercept."
The form you have it in is "point-slope"
"slope intercept form" comes in the form [tex]y=mx+b[/tex]
Therefore the form would be:
[tex]y=\frac{5}{4}x-\frac{15}{2}-7[/tex]
[tex]\boxed{y=\frac{5}{4}x-\frac{29}{2}}[/tex]
The form you have it in is "point-slope"
"slope intercept form" comes in the form [tex]y=mx+b[/tex]
Therefore the form would be:
[tex]y=\frac{5}{4}x-\frac{15}{2}-7[/tex]
[tex]\boxed{y=\frac{5}{4}x-\frac{29}{2}}[/tex]
y + 7 = 1 1/4(x - 6)
y + 7 = 1 1/4(x) - 5/4(6)
y + 7 = 1 1/4x - 7 1/2
+ 7 1/2 +7 1/2
y + 14 1/2 = 1 1/4x
y = mx + b
y = 1 1/4x + 14 1/2
y + 7 = 1 1/4(x) - 5/4(6)
y + 7 = 1 1/4x - 7 1/2
+ 7 1/2 +7 1/2
y + 14 1/2 = 1 1/4x
y = mx + b
y = 1 1/4x + 14 1/2
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.