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Sagot :
so which is equivilent
pemdas
(8-6x+12)
(20-6x)
multiply/distribute
1/4(20-6x)
5-6/4x=5-3/2x=-3/2x+5
the answer is D
so mean is equivilent to average
per minute means x feet for every one minute=xfeet/1miin=x/1
so just divide
-378/7=-54
mean change in altitude
-54 feet per minute
pemdas
(8-6x+12)
(20-6x)
multiply/distribute
1/4(20-6x)
5-6/4x=5-3/2x=-3/2x+5
the answer is D
so mean is equivilent to average
per minute means x feet for every one minute=xfeet/1miin=x/1
so just divide
-378/7=-54
mean change in altitude
-54 feet per minute
First Question:
[tex]\frac{1}{4}(8-6x+12) = [/tex]
[tex]\frac{8}{4}-\frac{6x}{4}+\frac{12}{4} = [/tex]
[tex]2-\frac{3}{2}x+3 = [/tex]
[tex]\boxed{(D) -\frac{3}{2}x+5}[/tex]
Second Question:
The average (mean) rate of change is just [tex]\dfrac{-378}{7} =\boxed{-54 ft/min} [/tex]
Hope this helps :D
[tex]\frac{1}{4}(8-6x+12) = [/tex]
[tex]\frac{8}{4}-\frac{6x}{4}+\frac{12}{4} = [/tex]
[tex]2-\frac{3}{2}x+3 = [/tex]
[tex]\boxed{(D) -\frac{3}{2}x+5}[/tex]
Second Question:
The average (mean) rate of change is just [tex]\dfrac{-378}{7} =\boxed{-54 ft/min} [/tex]
Hope this helps :D
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