Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
so which is equivilent
pemdas
(8-6x+12)
(20-6x)
multiply/distribute
1/4(20-6x)
5-6/4x=5-3/2x=-3/2x+5
the answer is D
so mean is equivilent to average
per minute means x feet for every one minute=xfeet/1miin=x/1
so just divide
-378/7=-54
mean change in altitude
-54 feet per minute
pemdas
(8-6x+12)
(20-6x)
multiply/distribute
1/4(20-6x)
5-6/4x=5-3/2x=-3/2x+5
the answer is D
so mean is equivilent to average
per minute means x feet for every one minute=xfeet/1miin=x/1
so just divide
-378/7=-54
mean change in altitude
-54 feet per minute
First Question:
[tex]\frac{1}{4}(8-6x+12) = [/tex]
[tex]\frac{8}{4}-\frac{6x}{4}+\frac{12}{4} = [/tex]
[tex]2-\frac{3}{2}x+3 = [/tex]
[tex]\boxed{(D) -\frac{3}{2}x+5}[/tex]
Second Question:
The average (mean) rate of change is just [tex]\dfrac{-378}{7} =\boxed{-54 ft/min} [/tex]
Hope this helps :D
[tex]\frac{1}{4}(8-6x+12) = [/tex]
[tex]\frac{8}{4}-\frac{6x}{4}+\frac{12}{4} = [/tex]
[tex]2-\frac{3}{2}x+3 = [/tex]
[tex]\boxed{(D) -\frac{3}{2}x+5}[/tex]
Second Question:
The average (mean) rate of change is just [tex]\dfrac{-378}{7} =\boxed{-54 ft/min} [/tex]
Hope this helps :D
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.