joshuaescobar275
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the price of milk in 2013 was around $3.28 a gallon. This was eight times as much as you would have probably paid for a gallon of milk in the 1950s. Whatwas the cost for a gallon of milk during the 1950s? show your calculations.

Sagot :

mathlovingguy
the price of the milk in the 1950s = x
8x =3.28
x = 3.28/8 =0.41$
so the price of the milk was 0.41$ a gallon


Amritanshup

The cost of the milk is [tex]\fbox{\$\,0.41{\text{ a gallon}}}[/tex] in 1950s.

Further explanation:

The price of milk in 2013 was around [tex]\$3.28[/tex] a gallon.

And it is given that this was eight times as much as one can would have probably paid for a gallon of milk in the 1950s.

It is given that the price of milk in 2013 is [tex]\$3.28[/tex] a gallon.

Assume the price of milk in 1950 be [tex]\$x[/tex] a gallon.

Now, given that 8 times of [tex]x[/tex] is the price of milk in 2013.

Therefore, [tex]8x[/tex] is the price of milk in 2013 and also [tex]\$3.28[/tex] is the price of milk in 2013.

Equating [tex]8x[/tex] and  [tex]\$3.28[/tex] equal as both are the price of milk in 2013 as,

[tex]\begin{aligned}8x&=3.28\\x&=\frac{{3.28}}{8}\\x&=0.41\\\end{aligned}[/tex]

Here, x is the price of milk in 1950.

Therefore, the cost of the milk is [tex]\fbox{\$\,0.41{\text{ a gallon}}}[/tex] in 1950s.

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Linear equations in one variable

Keywords: Cost, gallon, milk, linear equation in one variable, polynomials, variables, real numbers, degree of polynomials, equations, expressions, coefficients, zero polynomial, constants, integers, roots of polynomials.

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