Demonkid
Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

(6x^5+21x^4+33x^3+0x^3+18x+12)÷(6x+3)

Sagot :

apologiabiology
so first factor out the big equation on top
very hard
we can cancel out the 0x terms since 0x=0

so we notice that 3 is a factor of both equations
(6x+3)=(3)(2x+1)

and
(6x^5+21x^4+33x^3+18x+12)=(3)(2x+1)(x^4+3x^3+4x^2-2x+4
so we notice that there is a (3)(2x+1) in bot h so divide and cross them out

the answer is (x^4+3x^3+4x^2-2x+4)
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.