Demonkid
Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

(6x^5+21x^4+33x^3+0x^3+18x+12)÷(6x+3)

Sagot :

apologiabiology
so first factor out the big equation on top
very hard
we can cancel out the 0x terms since 0x=0

so we notice that 3 is a factor of both equations
(6x+3)=(3)(2x+1)

and
(6x^5+21x^4+33x^3+18x+12)=(3)(2x+1)(x^4+3x^3+4x^2-2x+4
so we notice that there is a (3)(2x+1) in bot h so divide and cross them out

the answer is (x^4+3x^3+4x^2-2x+4)
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.