Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

2x²+5=13
How do you find the value of x?

Sagot :

emilykay
2x²+5=13
subtract the 5 on both sides
2x²=8
divide by 2 on both sides
x²=4
put each side under the radical because of the exponent 2
√x²=√4
the radical cancels out the exponent 2; √4 = 2
x=2
heyDB
Since 5 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 5 from both sides.
2x^2=−5+13

Add −5 and 13 to get 8.
2x^2=8

Divide each term in the equation by 2.
x^2=4

Take the square root of both sides of the equation to eliminate the exponent on the left-hand side.
x=±√4

Rewrite 4 as 2^2
x=±√2^2

Pull terms out from under the radical.
x=±2

First, use the positive value of the ± to find the first solution.
x=2

Next, use the negative value of the ± to find the second solution.
x=−2


x=2,−2
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.