richkidz4L
Answered

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Given that a, b, and c are non-zero real numbers and a + b ≠ 0, solve for x.

ax + bx - c = 0

Sagot :

naǫ
[tex]ax+bx-c=0 \ \ \ |+c \\ ax+bx=c \\ (a+b)x=c \ \ \ |\div (a+b), a+b \not= 0 \\ \boxed{x=\frac{c}{a+b}}[/tex]
konrad509
[tex]ax+bx-c=0\\ x(a+b)=c\\ x=\dfrac{c}{a+b}[/tex]
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