Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

you want to create a box that can hold at the very longest a 4in object. find the dimensions of a box that will work

Sagot :

4×4×4 hope i help have a great day
AL2006

If you were working with a flat rectangle and you were given the diagonal,
you'd want to use the Pythagorean theorem to choose two sides whose
squares would add up to the square of the diagonal.

It works exactly the same with a 3-D box.  We need three dimensions for
the box, whose squares add up to the square of the diagonal between
opposite corners.  That's (4)² = 16.

So (L)² + (W²) + (H²) = 16 . From there, you're completely free to pick any
numbers you want, just as long as their squares add up to 16.  There are
an infinite number of possibilities.  Here are a few:

1 x 1 x √14

1 x 2 x √11

2 x 2 x √8

2 x 3 x √3

1 x 3 x √6


Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.