lisa200592
Answered

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what is the approximate volume of the cone with a height of 9 cm and a radius of 15 cm.

Sagot :

sugarmate
V = (1/3) pi r^2 h where r is the radius of the circular base and h is the height of the cone.

V = (1/3) pi (15)^2 * 9

V = 675 pi
V = 2120,575 square cm (approx)
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