Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A 12-foot ladder rests against the side of a house. The base of the ladder is 3 feet away from the side of the house. How high above the ground is the top of the ladder? Round to the nearest tenth of a foot.

Sagot :

M16man66
Using Pythagorean's Theorem we know that a^2 + b^2 = c^2
C is the length of the ladder, and we are given one of the sides, let's call that side b
                                                                                           _________
we have a^2 + b^2 = c^2, and a^2 = c^2 - b^2, so a = √ c^2 - b^2
        _________      ______     ____
a = √12^2-3^2 = √ 144-9 = √ 135 = 11.61895 
so the top of the ladder is 11.6 feet above the ground
This question is asking about the Pythagorean Theorem (A^2 + B^2 = C^2)

You know the length of the hypotenuse (this is 12 feet, the length of the ladder, which is C), you also know A, 3 feet from the side of the house.

So we have to plug into the formula what we know 3^2 + B^2 = 12^2, or 9 + B^2 = 144. By rearranging the formula you get 144 - 9 = B^2. Once you solve for B^2 you can take the square root to get B. (It's 11.6!)
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.